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(4x-3)(3x-1)(7x+2)(x+1)=(5x+1)(x+1)-10
We move all terms to the left:
(4x-3)(3x-1)(7x+2)(x+1)-((5x+1)(x+1)-10)=0
We multiply parentheses ..
(+12x^2-4x-9x+3)(7x+2)(x+1)-((5x+1)(x+1)-10)=0
We calculate terms in parentheses: -((5x+1)(x+1)-10), so:We get rid of parentheses
(5x+1)(x+1)-10
We multiply parentheses ..
(+5x^2+5x+x+1)-10
We get rid of parentheses
5x^2+5x+x+1-10
We add all the numbers together, and all the variables
5x^2+6x-9
Back to the equation:
-(5x^2+6x-9)
(+12x^2-4x-9x+3)(7x+2)(x+1)-5x^2-6x+9=0
We multiply parentheses ..
(+12x^2-4x-9x+3)(+7x^2+7x+2x+2)-5x^2-6x+9=0
We add all the numbers together, and all the variables
-5x^2+(+12x^2-4x-9x+3)(+7x^2+7x+2x+2)-6x+9=0
We move all terms containing x to the left, all other terms to the right
-5x^2+(+12x^2-4x-9x+3)(+7x^2+7x+2x+2)-6x=-9
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