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(4x-3)(3x-1)-(7x+2)(x+1)=(5x+1)(x+1)-10
We move all terms to the left:
(4x-3)(3x-1)-(7x+2)(x+1)-((5x+1)(x+1)-10)=0
We multiply parentheses ..
(+12x^2-4x-9x+3)-(7x+2)(x+1)-((5x+1)(x+1)-10)=0
We calculate terms in parentheses: -((5x+1)(x+1)-10), so:We get rid of parentheses
(5x+1)(x+1)-10
We multiply parentheses ..
(+5x^2+5x+x+1)-10
We get rid of parentheses
5x^2+5x+x+1-10
We add all the numbers together, and all the variables
5x^2+6x-9
Back to the equation:
-(5x^2+6x-9)
12x^2-5x^2-4x-9x-(7x+2)(x+1)-6x+3+9=0
We multiply parentheses ..
12x^2-5x^2-(+7x^2+7x+2x+2)-4x-9x-6x+3+9=0
We add all the numbers together, and all the variables
7x^2-(+7x^2+7x+2x+2)-19x+12=0
We get rid of parentheses
7x^2-7x^2-7x-2x-19x-2+12=0
We add all the numbers together, and all the variables
-28x+10=0
We move all terms containing x to the left, all other terms to the right
-28x=-10
x=-10/-28
x=5/14
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