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(4x-3)(3x-1)-(7x+2)(x+1)=(5x+1)(x-2)-10
We move all terms to the left:
(4x-3)(3x-1)-(7x+2)(x+1)-((5x+1)(x-2)-10)=0
We multiply parentheses ..
(+12x^2-4x-9x+3)-(7x+2)(x+1)-((5x+1)(x-2)-10)=0
We calculate terms in parentheses: -((5x+1)(x-2)-10), so:We get rid of parentheses
(5x+1)(x-2)-10
We multiply parentheses ..
(+5x^2-10x+x-2)-10
We get rid of parentheses
5x^2-10x+x-2-10
We add all the numbers together, and all the variables
5x^2-9x-12
Back to the equation:
-(5x^2-9x-12)
12x^2-5x^2-4x-9x-(7x+2)(x+1)+9x+3+12=0
We multiply parentheses ..
12x^2-5x^2-(+7x^2+7x+2x+2)-4x-9x+9x+3+12=0
We add all the numbers together, and all the variables
7x^2-(+7x^2+7x+2x+2)-4x+15=0
We get rid of parentheses
7x^2-7x^2-7x-2x-4x-2+15=0
We add all the numbers together, and all the variables
-13x+13=0
We move all terms containing x to the left, all other terms to the right
-13x=-13
x=-13/-13
x=1
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