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(4x-3)(5x-2)=
We move all terms to the left:
(4x-3)(5x-2)-()=0
We add all the numbers together, and all the variables
(4x-3)(5x-2)=0
We multiply parentheses ..
(+20x^2-8x-15x+6)=0
We get rid of parentheses
20x^2-8x-15x+6=0
We add all the numbers together, and all the variables
20x^2-23x+6=0
a = 20; b = -23; c = +6;
Δ = b2-4ac
Δ = -232-4·20·6
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-7}{2*20}=\frac{16}{40} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+7}{2*20}=\frac{30}{40} =3/4 $
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