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(4x-3)(7x+6)=16
We move all terms to the left:
(4x-3)(7x+6)-(16)=0
We multiply parentheses ..
(+28x^2+24x-21x-18)-16=0
We get rid of parentheses
28x^2+24x-21x-18-16=0
We add all the numbers together, and all the variables
28x^2+3x-34=0
a = 28; b = 3; c = -34;
Δ = b2-4ac
Δ = 32-4·28·(-34)
Δ = 3817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3817}}{2*28}=\frac{-3-\sqrt{3817}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3817}}{2*28}=\frac{-3+\sqrt{3817}}{56} $
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