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(4x-3)(7x-1)=0
We multiply parentheses ..
(+28x^2-4x-21x+3)=0
We get rid of parentheses
28x^2-4x-21x+3=0
We add all the numbers together, and all the variables
28x^2-25x+3=0
a = 28; b = -25; c = +3;
Δ = b2-4ac
Δ = -252-4·28·3
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-17}{2*28}=\frac{8}{56} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+17}{2*28}=\frac{42}{56} =3/4 $
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