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(4x-3)(8x+5)=0
We multiply parentheses ..
(+32x^2+20x-24x-15)=0
We get rid of parentheses
32x^2+20x-24x-15=0
We add all the numbers together, and all the variables
32x^2-4x-15=0
a = 32; b = -4; c = -15;
Δ = b2-4ac
Δ = -42-4·32·(-15)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*32}=\frac{-40}{64} =-5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*32}=\frac{48}{64} =3/4 $
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