(4x-3)+(10x-5)+(2x+21)+(95)+(6x-12)=360

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Solution for (4x-3)+(10x-5)+(2x+21)+(95)+(6x-12)=360 equation: 



(4x-3)+(10x-5)+(2x+21)+(95)+(6x-12)=360

We move all terms to the left:

(4x-3)+(10x-5)+(2x+21)+(95)+(6x-12)-(360)=0

We add all the numbers together, and all the variables

(4x-3)+(10x-5)+(2x+21)+(6x-12)-265=0

We get rid of parentheses

4x+10x+2x+6x-3-5+21-12-265=0

We add all the numbers together, and all the variables

22x-264=0

We move all terms containing x to the left, all other terms to the right

22x=264

x=264/22

x=12

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