(4x-3)+(2x)=36

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Solution for (4x-3)+(2x)=36 equation: 



(4x-3)+(2x)=36

We move all terms to the left:

(4x-3)+(2x)-(36)=0

We add all the numbers together, and all the variables

2x+(4x-3)-36=0

We get rid of parentheses

2x+4x-3-36=0

We add all the numbers together, and all the variables

6x-39=0

We move all terms containing x to the left, all other terms to the right

6x=39

x=39/6

x=6+1/2

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