(4x-3)+(2x-7)=20

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Solution for (4x-3)+(2x-7)=20 equation: 



(4x-3)+(2x-7)=20

We move all terms to the left:

(4x-3)+(2x-7)-(20)=0

We get rid of parentheses

4x+2x-3-7-20=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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