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(4x-3)+(3x+7)x=180
We move all terms to the left:
(4x-3)+(3x+7)x-(180)=0
We multiply parentheses
3x^2+(4x-3)+7x-180=0
We get rid of parentheses
3x^2+4x+7x-3-180=0
We add all the numbers together, and all the variables
3x^2+11x-183=0
a = 3; b = 11; c = -183;
Δ = b2-4ac
Δ = 112-4·3·(-183)
Δ = 2317
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{2317}}{2*3}=\frac{-11-\sqrt{2317}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{2317}}{2*3}=\frac{-11+\sqrt{2317}}{6} $
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