(4x-3)+(4x+10)+(6x-9)=180

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Solution for (4x-3)+(4x+10)+(6x-9)=180 equation: 



(4x-3)+(4x+10)+(6x-9)=180

We move all terms to the left:

(4x-3)+(4x+10)+(6x-9)-(180)=0

We get rid of parentheses

4x+4x+6x-3+10-9-180=0

We add all the numbers together, and all the variables

14x-182=0

We move all terms containing x to the left, all other terms to the right

14x=182

x=182/14

x=13

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