(4x-3)+(6x+3)+0=180

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Solution for (4x-3)+(6x+3)+0=180 equation: 



(4x-3)+(6x+3)+0=180

We move all terms to the left:

(4x-3)+(6x+3)+0-(180)=0

We add all the numbers together, and all the variables

(4x-3)+(6x+3)-180=0

We get rid of parentheses

4x+6x-3+3-180=0

We add all the numbers together, and all the variables

10x-180=0

We move all terms containing x to the left, all other terms to the right

10x=180

x=180/10

x=18

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