(4x-3)+(6x+3)=180-(9x+12)

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Solution for (4x-3)+(6x+3)=180-(9x+12) equation: 



(4x-3)+(6x+3)=180-(9x+12)

We move all terms to the left:

(4x-3)+(6x+3)-(180-(9x+12))=0

We get rid of parentheses

4x+6x-(180-(9x+12))-3+3=0



We calculate terms in parentheses: -(180-(9x+12)), so:

180-(9x+12)

determiningTheFunctionDomain
-(9x+12)+180

We get rid of parentheses

-9x-12+180

We add all the numbers together, and all the variables

-9x+168

Back to the equation:

-(-9x+168)



We add all the numbers together, and all the variables

10x-(-9x+168)=0

We get rid of parentheses

10x+9x-168=0

We add all the numbers together, and all the variables

19x-168=0

We move all terms containing x to the left, all other terms to the right

19x=168

x=168/19

x=8+16/19

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