(4x-3)+(x+28)=(7x-15)

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Solution for (4x-3)+(x+28)=(7x-15) equation:



(4x-3)+(x+28)=(7x-15)
We move all terms to the left:
(4x-3)+(x+28)-((7x-15))=0
We get rid of parentheses
4x+x-((7x-15))-3+28=0
We calculate terms in parentheses: -((7x-15)), so:
(7x-15)
We get rid of parentheses
7x-15
Back to the equation:
-(7x-15)
We add all the numbers together, and all the variables
5x-(7x-15)+25=0
We get rid of parentheses
5x-7x+15+25=0
We add all the numbers together, and all the variables
-2x+40=0
We move all terms containing x to the left, all other terms to the right
-2x=-40
x=-40/-2
x=+20

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