(4x-3)+(x+28)=(7x-15)

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Solution for (4x-3)+(x+28)=(7x-15) equation: 



(4x-3)+(x+28)=(7x-15)

We move all terms to the left:

(4x-3)+(x+28)-((7x-15))=0

We get rid of parentheses

4x+x-((7x-15))-3+28=0



We calculate terms in parentheses: -((7x-15)), so:

(7x-15)

We get rid of parentheses

7x-15

Back to the equation:

-(7x-15)



We add all the numbers together, and all the variables

5x-(7x-15)+25=0

We get rid of parentheses

5x-7x+15+25=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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