(4x-3)+(x+8)=(2x-5)

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Solution for (4x-3)+(x+8)=(2x-5) equation:



(4x-3)+(x+8)=(2x-5)
We move all terms to the left:
(4x-3)+(x+8)-((2x-5))=0
We get rid of parentheses
4x+x-((2x-5))-3+8=0
We calculate terms in parentheses: -((2x-5)), so:
(2x-5)
We get rid of parentheses
2x-5
Back to the equation:
-(2x-5)
We add all the numbers together, and all the variables
5x-(2x-5)+5=0
We get rid of parentheses
5x-2x+5+5=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3

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