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(4x-3)-(2-x)=(3x+1)-(2x-10)
We move all terms to the left:
(4x-3)-(2-x)-((3x+1)-(2x-10))=0
We add all the numbers together, and all the variables
(4x-3)-(-1x+2)-((3x+1)-(2x-10))=0
We get rid of parentheses
4x+1x-((3x+1)-(2x-10))-3-2=0
We calculate terms in parentheses: -((3x+1)-(2x-10)), so:We add all the numbers together, and all the variables
(3x+1)-(2x-10)
We get rid of parentheses
3x-2x+1+10
We add all the numbers together, and all the variables
x+11
Back to the equation:
-(x+11)
5x-(x+11)-5=0
We get rid of parentheses
5x-x-11-5=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4
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