(4x-3)-(7-2x)=2

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Solution for (4x-3)-(7-2x)=2 equation:



(4x-3)-(7-2x)=2
We move all terms to the left:
(4x-3)-(7-2x)-(2)=0
We add all the numbers together, and all the variables
(4x-3)-(-2x+7)-2=0
We get rid of parentheses
4x+2x-3-7-2=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2

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