(4x-3)/12=(2x+3)/6

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Solution for (4x-3)/12=(2x+3)/6 equation: 



(4x-3)/12=(2x+3)/6

We move all terms to the left:

(4x-3)/12-((2x+3)/6)=0

We calculate fractions


4x/()+(-((2x+3)*12)/()=0



We calculate terms in parentheses: +(-((2x+3)*12)/(), so:

-((2x+3)*12)/(

We multiply all the terms by the denominator


-((2x+3)*12)



We calculate terms in parentheses: -((2x+3)*12), so:

(2x+3)*12

We multiply parentheses

24x+36

Back to the equation:

-(24x+36)



We get rid of parentheses

-24x-36

Back to the equation:

+(-24x-36)



We get rid of parentheses

4x/()-24x-36=0

We multiply all the terms by the denominator


4x-24x*()-36*()=0

We add all the numbers together, and all the variables

4x-24x*()=0

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