(4x-3)/15=(x+3)/5

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Solution for (4x-3)/15=(x+3)/5 equation: 



(4x-3)/15=(x+3)/5

We move all terms to the left:

(4x-3)/15-((x+3)/5)=0

We calculate fractions


4x/()+(-((x+3)*15)/()=0



We calculate terms in parentheses: +(-((x+3)*15)/(), so:

-((x+3)*15)/(

We multiply all the terms by the denominator


-((x+3)*15)



We calculate terms in parentheses: -((x+3)*15), so:

(x+3)*15

We multiply parentheses

15x+45

Back to the equation:

-(15x+45)



We get rid of parentheses

-15x-45

Back to the equation:

+(-15x-45)



We get rid of parentheses

4x/()-15x-45=0

We multiply all the terms by the denominator


4x-15x*()-45*()=0

We add all the numbers together, and all the variables

4x-15x*()=0

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