(4x-3)/4+(x-3)/5=(x+6)/4

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Solution for (4x-3)/4+(x-3)/5=(x+6)/4 equation: 



(4x-3)/4+(x-3)/5=(x+6)/4

We move all terms to the left:

(4x-3)/4+(x-3)/5-((x+6)/4)=0

We calculate fractions


(20x-15)/()+x/()+(-((x+6)*5)/()=0



We calculate terms in parentheses: +(-((x+6)*5)/(), so:

-((x+6)*5)/(

We multiply all the terms by the denominator


-((x+6)*5)



We calculate terms in parentheses: -((x+6)*5), so:

(x+6)*5

We multiply parentheses

5x+30

Back to the equation:

-(5x+30)



We get rid of parentheses

-5x-30

Back to the equation:

+(-5x-30)



We get rid of parentheses

(20x-15)/()+x/()-5x-30=0

We multiply all the terms by the denominator


(20x-15)+x-5x*()-30*()=0

We add all the numbers together, and all the variables

x+(20x-15)-5x*()=0

We get rid of parentheses

x+20x-5x*()-15=0

We add all the numbers together, and all the variables

21x-5x*()-15=0

We move all terms containing x to the left, all other terms to the right

21x-5x*()=15

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