(4x-3)/4x-4=1/5

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Solution for (4x-3)/4x-4=1/5 equation: 



(4x-3)/4x-4=1/5

We move all terms to the left:

(4x-3)/4x-4-(1/5)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



We add all the numbers together, and all the variables

(4x-3)/4x-4-(+1/5)=0

We get rid of parentheses

(4x-3)/4x-4-1/5=0

We calculate fractions


(20x-15)/20x+(-4x)/20x-4=0

We multiply all the terms by the denominator


(20x-15)+(-4x)-4*20x=0

Wy multiply elements

(20x-15)+(-4x)-80x=0

We get rid of parentheses

20x-4x-80x-15=0

We add all the numbers together, and all the variables

-64x-15=0

We move all terms containing x to the left, all other terms to the right

-64x=15

x=15/-64

x=-15/64

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