(4x-3)2+(4x+3)2=25

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Solution for (4x-3)2+(4x+3)2=25 equation: 



(4x-3)2+(4x+3)2=25

We move all terms to the left:

(4x-3)2+(4x+3)2-(25)=0

We multiply parentheses

8x+8x-6+6-25=0

We add all the numbers together, and all the variables

16x-25=0

We move all terms containing x to the left, all other terms to the right

16x=25

x=25/16

x=1+9/16

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