(4x-3)=4(6x+4)-4

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Solution for (4x-3)=4(6x+4)-4 equation:



(4x-3)=4(6x+4)-4
We move all terms to the left:
(4x-3)-(4(6x+4)-4)=0
We get rid of parentheses
4x-(4(6x+4)-4)-3=0
We calculate terms in parentheses: -(4(6x+4)-4), so:
4(6x+4)-4
We multiply parentheses
24x+16-4
We add all the numbers together, and all the variables
24x+12
Back to the equation:
-(24x+12)
We get rid of parentheses
4x-24x-12-3=0
We add all the numbers together, and all the variables
-20x-15=0
We move all terms containing x to the left, all other terms to the right
-20x=15
x=15/-20
x=-3/4

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