(4x-3/3x-3)=(x-17/x-7)

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Solution for (4x-3/3x-3)=(x-17/x-7) equation: 



(4x-3/3x-3)=(x-17/x-7)

We move all terms to the left:

(4x-3/3x-3)-((x-17/x-7))=0



Domain of the equation: 3x-3)!=0

x∈R





Domain of the equation: x-7))!=0

x∈R



We get rid of parentheses

4x-3/3x-((x-17/x-7))-3=0

We calculate fractions


4x+(-3x)/3x^2+(-((x-17*3x)/3x^2-3=0

We add all the numbers together, and all the variables

4x+(-3x)/3x^2+(-((+x-17*3x)/3x^2-3=0

We calculate fractions

We do not support expression: x^4

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