(4x-30)+(3x+15)=180

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Solution for (4x-30)+(3x+15)=180 equation: 



(4x-30)+(3x+15)=180

We move all terms to the left:

(4x-30)+(3x+15)-(180)=0

We get rid of parentheses

4x+3x-30+15-180=0

We add all the numbers together, and all the variables

7x-195=0

We move all terms containing x to the left, all other terms to the right

7x=195

x=195/7

x=27+6/7

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