(4x-30)=(3x+15)

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Solution for (4x-30)=(3x+15) equation: 



(4x-30)=(3x+15)

We move all terms to the left:

(4x-30)-((3x+15))=0

We get rid of parentheses

4x-((3x+15))-30=0



We calculate terms in parentheses: -((3x+15)), so:

(3x+15)

We get rid of parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

4x-3x-15-30=0

We add all the numbers together, and all the variables

x-45=0

We move all terms containing x to the left, all other terms to the right

x=45

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