(4x-30)=(x+55)

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Solution for (4x-30)=(x+55) equation: 



(4x-30)=(x+55)

We move all terms to the left:

(4x-30)-((x+55))=0

We get rid of parentheses

4x-((x+55))-30=0



We calculate terms in parentheses: -((x+55)), so:

(x+55)

We get rid of parentheses

x+55

Back to the equation:

-(x+55)



We get rid of parentheses

4x-x-55-30=0

We add all the numbers together, and all the variables

3x-85=0

We move all terms containing x to the left, all other terms to the right

3x=85

x=85/3

x=28+1/3

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