(4x-33)=(3x+10)

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Solution for (4x-33)=(3x+10) equation: 



(4x-33)=(3x+10)

We move all terms to the left:

(4x-33)-((3x+10))=0

We get rid of parentheses

4x-((3x+10))-33=0



We calculate terms in parentheses: -((3x+10)), so:

(3x+10)

We get rid of parentheses

3x+10

Back to the equation:

-(3x+10)



We get rid of parentheses

4x-3x-10-33=0

We add all the numbers together, and all the variables

x-43=0

We move all terms containing x to the left, all other terms to the right

x=43

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