(4x-33)=(3x+7)

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Solution for (4x-33)=(3x+7) equation: 



(4x-33)=(3x+7)

We move all terms to the left:

(4x-33)-((3x+7))=0

We get rid of parentheses

4x-((3x+7))-33=0



We calculate terms in parentheses: -((3x+7)), so:

(3x+7)

We get rid of parentheses

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

4x-3x-7-33=0

We add all the numbers together, and all the variables

x-40=0

We move all terms containing x to the left, all other terms to the right

x=40

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