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(4x-4)(2x+5)=4x(5)+-4(2x)+-4(5)
We move all terms to the left:
(4x-4)(2x+5)-(4x(5)+-4(2x)+-4(5))=0
We add all the numbers together, and all the variables
-(+4x^5-42x++-45)+(4x-4)(2x+5)=0
We use the square of the difference formula
-(+4x^5-42x+-45)+(4x-4)(2x+5)=0
We get rid of parentheses
-4x^5+42x+(4x-4)(2x+5)-45=0
We multiply parentheses ..
-4x^5+(+8x^2+20x-8x-20)+42x-45=0
We do not support expression: x^5
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