(4x-4)(2x+5)=4x(5)+-4(2x)+-4(5)

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Solution for (4x-4)(2x+5)=4x(5)+-4(2x)+-4(5) equation: 



(4x-4)(2x+5)=4x(5)+-4(2x)+-4(5)

We move all terms to the left:

(4x-4)(2x+5)-(4x(5)+-4(2x)+-4(5))=0

We add all the numbers together, and all the variables

-(+4x^5-42x++-45)+(4x-4)(2x+5)=0

We use the square of the difference formula

-(+4x^5-42x+-45)+(4x-4)(2x+5)=0

We get rid of parentheses

-4x^5+42x+(4x-4)(2x+5)-45=0

We multiply parentheses ..

-4x^5+(+8x^2+20x-8x-20)+42x-45=0

We do not support expression: x^5

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