(4x-4)(x-1)=-32x-32

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Solution for (4x-4)(x-1)=-32x-32 equation: 



(4x-4)(x-1)=-32x-32

We move all terms to the left:

(4x-4)(x-1)-(-32x-32)=0

We get rid of parentheses

(4x-4)(x-1)+32x+32=0

We multiply parentheses ..

(+4x^2-4x-4x+4)+32x+32=0

We get rid of parentheses

4x^2-4x-4x+32x+4+32=0

We add all the numbers together, and all the variables

4x^2+24x+36=0

a = 4; b = 24; c = +36;
Δ = b2-4ac
Δ = 242-4·4·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-24}{8}=-3$

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