(4x-4)+(0.5x+32)+80=180

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Solution for (4x-4)+(0.5x+32)+80=180 equation: 



(4x-4)+(0.5x+32)+80=180

We move all terms to the left:

(4x-4)+(0.5x+32)+80-(180)=0

We add all the numbers together, and all the variables

(4x-4)+(0.5x+32)-100=0

We get rid of parentheses

4x+0.5x-4+32-100=0

We add all the numbers together, and all the variables

4.5x-72=0

We move all terms containing x to the left, all other terms to the right

4.5x=72

x=72/4.5

x=16

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