(4x-4)+(3x-2)+(2x+6)=180

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Solution for (4x-4)+(3x-2)+(2x+6)=180 equation: 



(4x-4)+(3x-2)+(2x+6)=180

We move all terms to the left:

(4x-4)+(3x-2)+(2x+6)-(180)=0

We get rid of parentheses

4x+3x+2x-4-2+6-180=0

We add all the numbers together, and all the variables

9x-180=0

We move all terms containing x to the left, all other terms to the right

9x=180

x=180/9

x=20

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