(4x-4)+(3x-2)+2x+6)=180

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Solution for (4x-4)+(3x-2)+2x+6)=180 equation: 



(4x-4)+(3x-2)+2x+6)=180

We move all terms to the left:

(4x-4)+(3x-2)+2x+6)-(180)=0

We add all the numbers together, and all the variables

2x+(4x-4)+(3x-2)=0

We get rid of parentheses

2x+4x+3x-4-2=0

We add all the numbers together, and all the variables

9x-6=0

We move all terms containing x to the left, all other terms to the right

9x=6

x=6/9

x=2/3

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