(4x-4)/2=(2x+8)/6

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Solution for (4x-4)/2=(2x+8)/6 equation: 



(4x-4)/2=(2x+8)/6

We move all terms to the left:

(4x-4)/2-((2x+8)/6)=0

We calculate fractions


4x/()+(-((2x+8)*2)/()=0



We calculate terms in parentheses: +(-((2x+8)*2)/(), so:

-((2x+8)*2)/(

We multiply all the terms by the denominator


-((2x+8)*2)



We calculate terms in parentheses: -((2x+8)*2), so:

(2x+8)*2

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

-4x-16

Back to the equation:

+(-4x-16)



We get rid of parentheses

4x/()-4x-16=0

We multiply all the terms by the denominator


4x-4x*()-16*()=0

We add all the numbers together, and all the variables

4x-4x*()=0

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