(4x-41)=(6x+10)

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Solution for (4x-41)=(6x+10) equation: 



(4x-41)=(6x+10)

We move all terms to the left:

(4x-41)-((6x+10))=0

We get rid of parentheses

4x-((6x+10))-41=0



We calculate terms in parentheses: -((6x+10)), so:

(6x+10)

We get rid of parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

4x-6x-10-41=0

We add all the numbers together, and all the variables

-2x-51=0

We move all terms containing x to the left, all other terms to the right

-2x=51

x=51/-2

x=-25+1/2

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