(4x-42)+(3x+12)=180

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Solution for (4x-42)+(3x+12)=180 equation: 



(4x-42)+(3x+12)=180

We move all terms to the left:

(4x-42)+(3x+12)-(180)=0

We get rid of parentheses

4x+3x-42+12-180=0

We add all the numbers together, and all the variables

7x-210=0

We move all terms containing x to the left, all other terms to the right

7x=210

x=210/7

x=30

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