(4x-43)+(2x+31)=180

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Solution for (4x-43)+(2x+31)=180 equation: 



(4x-43)+(2x+31)=180

We move all terms to the left:

(4x-43)+(2x+31)-(180)=0

We get rid of parentheses

4x+2x-43+31-180=0

We add all the numbers together, and all the variables

6x-192=0

We move all terms containing x to the left, all other terms to the right

6x=192

x=192/6

x=32

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