(4x-5)(-3x+7)=-2x(9+6x)

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Solution for (4x-5)(-3x+7)=-2x(9+6x) equation: 



(4x-5)(-3x+7)=-2x(9+6x)

We move all terms to the left:

(4x-5)(-3x+7)-(-2x(9+6x))=0

We add all the numbers together, and all the variables

(4x-5)(-3x+7)-(-2x(6x+9))=0

We multiply parentheses ..

(-12x^2+28x+15x-35)-(-2x(6x+9))=0



We calculate terms in parentheses: -(-2x(6x+9)), so:

-2x(6x+9)

We multiply parentheses

-12x^2-18x

Back to the equation:

-(-12x^2-18x)



We get rid of parentheses

-12x^2+12x^2+28x+15x+18x-35=0

We add all the numbers together, and all the variables

61x-35=0

We move all terms containing x to the left, all other terms to the right

61x=35

x=35/61

x=35/61

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