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(4x-5)(10-x)=0
We add all the numbers together, and all the variables
(4x-5)(-1x+10)=0
We multiply parentheses ..
(-4x^2+40x+5x-50)=0
We get rid of parentheses
-4x^2+40x+5x-50=0
We add all the numbers together, and all the variables
-4x^2+45x-50=0
a = -4; b = 45; c = -50;
Δ = b2-4ac
Δ = 452-4·(-4)·(-50)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-35}{2*-4}=\frac{-80}{-8} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+35}{2*-4}=\frac{-10}{-8} =1+1/4 $
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