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(4x-5)(x+17)=63
We move all terms to the left:
(4x-5)(x+17)-(63)=0
We multiply parentheses ..
(+4x^2+68x-5x-85)-63=0
We get rid of parentheses
4x^2+68x-5x-85-63=0
We add all the numbers together, and all the variables
4x^2+63x-148=0
a = 4; b = 63; c = -148;
Δ = b2-4ac
Δ = 632-4·4·(-148)
Δ = 6337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{6337}}{2*4}=\frac{-63-\sqrt{6337}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{6337}}{2*4}=\frac{-63+\sqrt{6337}}{8} $
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