(4x-5)+(2x+3)=(x+6)+(3x-12)

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Solution for (4x-5)+(2x+3)=(x+6)+(3x-12) equation: 



(4x-5)+(2x+3)=(x+6)+(3x-12)

We move all terms to the left:

(4x-5)+(2x+3)-((x+6)+(3x-12))=0

We get rid of parentheses

4x+2x-((x+6)+(3x-12))-5+3=0



We calculate terms in parentheses: -((x+6)+(3x-12)), so:

(x+6)+(3x-12)

We get rid of parentheses

x+3x+6-12

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

6x-(4x-6)-2=0

We get rid of parentheses

6x-4x+6-2=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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