(4x-5)+(3x+5)=40

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Solution for (4x-5)+(3x+5)=40 equation: 



(4x-5)+(3x+5)=40

We move all terms to the left:

(4x-5)+(3x+5)-(40)=0

We get rid of parentheses

4x+3x-5+5-40=0

We add all the numbers together, and all the variables

7x-40=0

We move all terms containing x to the left, all other terms to the right

7x=40

x=40/7

x=5+5/7

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