(4x-5)+(3y+1)=

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Solution for (4x-5)+(3y+1)= equation:


Simplifying
(4x + -5) + (3y + 1) = 0

Reorder the terms:
(-5 + 4x) + (3y + 1) = 0

Remove parenthesis around (-5 + 4x)
-5 + 4x + (3y + 1) = 0

Reorder the terms:
-5 + 4x + (1 + 3y) = 0

Remove parenthesis around (1 + 3y)
-5 + 4x + 1 + 3y = 0

Reorder the terms:
-5 + 1 + 4x + 3y = 0

Combine like terms: -5 + 1 = -4
-4 + 4x + 3y = 0

Solving
-4 + 4x + 3y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4x + 4 + 3y = 0 + 4

Reorder the terms:
-4 + 4 + 4x + 3y = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4x + 3y = 0 + 4
4x + 3y = 0 + 4

Combine like terms: 0 + 4 = 4
4x + 3y = 4

Add '-3y' to each side of the equation.
4x + 3y + -3y = 4 + -3y

Combine like terms: 3y + -3y = 0
4x + 0 = 4 + -3y
4x = 4 + -3y

Divide each side by '4'.
x = 1 + -0.75y

Simplifying
x = 1 + -0.75y

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