(4x-5)+(4x+20)+(5x-5)+x=360

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Solution for (4x-5)+(4x+20)+(5x-5)+x=360 equation: 



(4x-5)+(4x+20)+(5x-5)+x=360

We move all terms to the left:

(4x-5)+(4x+20)+(5x-5)+x-(360)=0

We add all the numbers together, and all the variables

x+(4x-5)+(4x+20)+(5x-5)-360=0

We get rid of parentheses

x+4x+4x+5x-5+20-5-360=0

We add all the numbers together, and all the variables

14x-350=0

We move all terms containing x to the left, all other terms to the right

14x=350

x=350/14

x=25

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