(4x-5)-(2+3x)=7(x-6)

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Solution for (4x-5)-(2+3x)=7(x-6) equation:



(4x-5)-(2+3x)=7(x-6)
We move all terms to the left:
(4x-5)-(2+3x)-(7(x-6))=0
We add all the numbers together, and all the variables
(4x-5)-(3x+2)-(7(x-6))=0
We get rid of parentheses
4x-3x-(7(x-6))-5-2=0
We calculate terms in parentheses: -(7(x-6)), so:
7(x-6)
We multiply parentheses
7x-42
Back to the equation:
-(7x-42)
We add all the numbers together, and all the variables
x-(7x-42)-7=0
We get rid of parentheses
x-7x+42-7=0
We add all the numbers together, and all the variables
-6x+35=0
We move all terms containing x to the left, all other terms to the right
-6x=-35
x=-35/-6
x=5+5/6

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