(4x-5)-6=12x-(1x+4)-(3x+7)

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Solution for (4x-5)-6=12x-(1x+4)-(3x+7) equation:



(4x-5)-6=12x-(1x+4)-(3x+7)
We move all terms to the left:
(4x-5)-6-(12x-(1x+4)-(3x+7))=0
We add all the numbers together, and all the variables
(4x-5)-(12x-(x+4)-(3x+7))-6=0
We get rid of parentheses
4x-(12x-(x+4)-(3x+7))-5-6=0
We calculate terms in parentheses: -(12x-(x+4)-(3x+7)), so:
12x-(x+4)-(3x+7)
We get rid of parentheses
12x-x-3x-4-7
We add all the numbers together, and all the variables
8x-11
Back to the equation:
-(8x-11)
We add all the numbers together, and all the variables
4x-(8x-11)-11=0
We get rid of parentheses
4x-8x+11-11=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0

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