(4x-5)/(3-7x)=2

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Solution for (4x-5)/(3-7x)=2 equation: 


D( x )

3-(7*x) = 0

3-(7*x) = 0

3-(7*x) = 0

3-7*x = 0

3-7*x = 0 // - 3

-7*x = -3 // : -7

x = -3/(-7)

x = 3/7

x in (-oo:3/7) U (3/7:+oo)

(4*x-5)/(3-(7*x)) = 2 // - 2

(4*x-5)/(3-(7*x))-2 = 0

(4*x-5)/(3-7*x)-2 = 0

(4*x-5)/(3-7*x)+(-2*(3-7*x))/(3-7*x) = 0

4*x-2*(3-7*x)-5 = 0

18*x-11 = 0

(18*x-11)/(3-7*x) = 0

(18*x-11)/(3-7*x) = 0 // * 3-7*x

18*x-11 = 0

18*x-11 = 0 // + 11

18*x = 11 // : 18

x = 11/18

x = 11/18

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