(4x-5)/3=(3x+7)/2

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Solution for (4x-5)/3=(3x+7)/2 equation: 



(4x-5)/3=(3x+7)/2

We move all terms to the left:

(4x-5)/3-((3x+7)/2)=0

We calculate fractions


4x/()+(-((3x+7)*3)/()=0



We calculate terms in parentheses: +(-((3x+7)*3)/(), so:

-((3x+7)*3)/(

We multiply all the terms by the denominator


-((3x+7)*3)



We calculate terms in parentheses: -((3x+7)*3), so:

(3x+7)*3

We multiply parentheses

9x+21

Back to the equation:

-(9x+21)



We get rid of parentheses

-9x-21

Back to the equation:

+(-9x-21)



We get rid of parentheses

4x/()-9x-21=0

We multiply all the terms by the denominator


4x-9x*()-21*()=0

We add all the numbers together, and all the variables

4x-9x*()=0

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